a)
ms = 800g, c% = 2%
c% = mdx100/ms
=> md = msxc%/100 = 800x2/100 = 16g Br2
a L 16g n moli
C4H8 + Br2 --CCl4--> C4H8Br2
22,4 160 1
=> a = 22,4x16/160 = 2,24 L C4H8 pur
80% ..................... 2,24 L pur
100% ..................... V.impur = 2,8 L C4H8
b)
=> n = 16x1/160 = 0,1 moli produs obtinut teoretic la 100%........... dar la 85%...?
100% ............................ 0,1 moli produs
85% ............................ Cp = 0,085 moli produs
