VA ROOOG 50 DE PUNCTE REZOLVAREA COMPLETA
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m(∡A)+m(∡B)+m(∡ACB)=180°
m(∡B)=2*m(∡ACB)
Fie m(∡A)=x; m(∡B)=y, m(∡C)=z
x+y+z=180°
90°+y+z=180°
y+z=180°-90°=90°
y=2z⇒y+z=2z+z=3z
3z=90°⇒z=90°/3=30°
⇒m(∡ACB)=30°
m(∡ACB)+m(∡BCD)=180°
⇒m(∡BCD)=180°-30°=150°