ex 15 va rog sa ma ajutati Ex ala cu Determina......
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Răspuns:
{[(x-8)×7+6-5]-4}×3-2=10
{[(x-8)×7+6-5]-4}×3=10+2
{[(x-8)×7+6-5]-4}×3=12
{[(x-8)×7+6-5]-4}=12÷3
{[(x-8)×7+6-5]-4}=4
[(x-8)×7+6-5]=4+4
[(x-8)×7+6-5]=8
[(x-8)×7+6]=8+5
[(x-8)×7+6]=13
[(x-8)×7]=13-6
[(x-8)×7]=7
x-8=7÷7
x-8=1
x=8+1
x=9