Răspuns:
y=2sin10t
viteza unghiulara=ω=10
ω=2π/T
T=2π/ω
T=2π/10=π/5
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elongatia
y=2sin10*(π/5)/12=2sin2π/12=2sinπ/6=2*1/2=1
v=ωAcos(ωt1
v=10*2 cos10*(π/5)/12=
20cos10π/5)/12)=20cos10π/60=20*cosπ/6=20√3/2=10√3cm/s
a=-ω²Asin(ωt)=
-100*2*sin(10(π/5)/12
=-200sin10π/60=
-200sin/6=-200*1/2= -100
Explicație:
