Răspuns:
[tex]a = 4 \sqrt{33} \div \sqrt{11} + 14 \sqrt{30} \div (2 \sqrt{10} - 3 \times 2 \sqrt{10} ) + 9 \sqrt{39} \div \sqrt{13 } \\ a = 4 \sqrt{3} + 7 \sqrt{3} - 6 \sqrt{3} + 9 \sqrt{3} \\ a = 14 \sqrt{3} [/tex]
[tex]b = 3 \sqrt{2} \times 3 \sqrt{3} + 4 \sqrt{6} \times ( - 2) - 4 \sqrt{2} \times \sqrt{3} + \sqrt{2} \times \sqrt{3} \\ b = 9 \sqrt{6} - 8 \sqrt{6} - 4 \sqrt{6} + \sqrt{6} \\ b = - 2 \sqrt{6} [/tex]
