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Calculand 4√24(9 supra √18 - 4 supra√12)-5(√27-√32) este egal cu?

Răspuns :

Răspuns:

[tex]9 \sqrt{3} + 4 \sqrt{2} [/tex]

Explicație pas cu pas:

[tex]4 \times 2 \sqrt{6} ( \frac{9}{3 \sqrt{2} } - \frac{4}{2 \sqrt{3} } ) - 5(3 \sqrt{3} - 4 \sqrt{2} )[/tex]

[tex]8 \sqrt{6} ( \frac{3}{ \sqrt{2} } - \frac{2}{ \sqrt{3} } ) - 15 \sqrt{3} + 20 \sqrt{2} [/tex]

[tex]8 \sqrt{6} ( \frac{3 \sqrt{2} }{2} - \frac{2 \sqrt{3} }{3} ) - 15 \sqrt{3} + 20 \sqrt{2} [/tex]

[tex]12 \sqrt{12} - \frac{16 \sqrt{18} }{3} - 15 \sqrt{3} + 20 \sqrt{2} [/tex]

[tex]24 \sqrt{3} - \frac{48 \sqrt{2} }{3} - 15 \sqrt{3} + 20 \sqrt{2} [/tex]

[tex]24 \sqrt{3} - 16 \sqrt{2 } - 15 \sqrt{ 3} + 20 \sqrt{2} [/tex]

[tex]9 \sqrt{3} + 4 \sqrt{2} [/tex]

Sper ca te-am ajutat