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f(x)=3x² – 2x - 5: vă rog frumos​

Răspuns :

f(x)=3x^2-2x-5
a=3. b=-2. c=-5

delta=b^2-4*a*c
=(-2)^2-4*3*(-5)
=4-12*(-5)
=4+60
=64
Delta>0=>x1,2=-b+-radical din delta/2a
X1=2+8/2*3
=10/6
=5/3

X2=2-8/6
=-6/6
=-1

=>x apartine {-1;5/3}