A Ca=40; A O=16; A Na=23; A H=1; A C=12
M(CaO) = 40+16=56g/mol
M(NaOH)=23+16+1=40g/mol
M(CO) = 12+16=28g/mol
M(C2H2)=12×2+1×2=26g/mol
M(CaCO3)=40+12+16×3=40+12+48=100g_mol
M-masa molara
Rapoartele masice:
CaO 40:16=5:2
NaOH 23:16:1
CO 12:16=3:4
C2H2 24:2=12:1
CaCO3 40:12:48=10:3:12