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Daca a=3 si b+c=5,calculează:

B+c-a,

Ab+ac,

3b+3c,

3a+5*(2a-3),

2*(a+3)-5,

26-3*(a+1)+4b+4c-2a,

A+2b+2c



Răspuns :

Răspuns:

5-3=2

3*5=15

3*5=15

3*3+5*(6-3)=9+5*3=9+15=24

2*(3+3)-5=2*6-5=12-5=7

26-3*(3+1)+4*5-2*3=26-3*4+20-6=26-12+14=28

3+2*5=3+10=13