Răspuns:
a) [tex]\sqrt{6\frac{1}{4} } =\sqrt{\frac{6*4+1} 4} =\sqrt{\frac{25}{4} } =\frac{5}{4}[/tex] ∈ Q
b) [tex]\sqrt{0,(4)} =\sqrt{\frac{4}{9} } =\frac{2}{3}[/tex] ∈ Q
c) [tex]\sqrt{2^{2}*3^{6} } =\sqrt{(2*3^{3})^{2} } =2*3^{3}=54[/tex] ∈ Q
d) [tex]-\sqrt{2\frac{7}{9} } =-\sqrt{\frac{25}{9} } =-\frac{5}{3}[/tex] ∈ Q
e) [tex]\sqrt{1,5625} =1.25[/tex] ∈ Q
Explicație pas cu pas:
