[tex]\it 3)\ 6\sqrt2:\sqrt3+4\sqrt6=6\cdot\dfrac{^{\sqrt3)}\sqrt2}{\ \sqrt3}+4\sqrt6=6\cdot\dfrac{\sqrt6}{3}+4\sqrt6=2\sqrt6+4\sqrt6=6\sqrt6\\ \\ 4)\ \sqrt{3^2+4^2}-5=\sqrt{9+16}-5=\sqrt{25}-5=5-5=0\\ \\ 5)\ \sqrt{45}:\sqrt5+2015^0=\sqrt{45:5}+1=\sqrt9+1=3+1=4[/tex]
