Răspuns:
Explicație:
1.
-se afla nr. de moli de Cl2 din 710g Cl2
MCl2=2.35,5 =71-------> 71g/moli
n= 710g : 71g/moli=10moli Cl2
ZCl=17 -------> 17 p , 17 e
1mol Cl2---------2 . 6,023.10²³atomi Cl------------2 . 17 . 6,023. 10²³ p
10 moli Cl2--------------------------------------------------x p
x=10 . 2 .17 . 6,023.10²³ p = 2047,82 .10²³ p
2.
2160kg=2160000g
ZAg =47---------> 47 p ,47 e
A=108
n=2160000g: 108g/moli=20000moli Ag
1molAg ----------6,023.10²³atomi Ag---------47 . 6,023.10²³ p
20000moli--------------------------------------------------x p
x= 20000 . 47 .6,023.10²³ p = 5661620.10²³ p
