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Rezolvați ecuațiile. Mulțumesc mult !!!

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Răspuns :

Salutare!

[tex]\bf h)\: 0,(3)x+ 1,5=1[/tex]

[tex]\bf \dfrac{3}{9}\cdot x+ \dfrac{15}{10}=1[/tex]

[tex]\bf \dfrac{\not3}{\not9}\cdot x+ \dfrac{\not15}{\not10}=1[/tex]

[tex]\bf \dfrac{1}{3}\cdot x+ \dfrac{3}{2}=1\:\:\:|\cdot 6[/tex]

[tex]\bf 6\cdot\dfrac{1}{3}\cdot x+ 6\cdot\dfrac{3}{2}=6\cdot 1[/tex]

[tex]\bf \not6\cdot\dfrac{1}{\not3}\cdot x+ \not6\cdot\dfrac{3}{\not2}=6[/tex]

[tex]\bf 2x+9=6[/tex]

[tex]\bf 2x=6-9[/tex]

[tex]\bf 2x=-3[/tex]

[tex]\boxed{\bf x=-\dfrac{3}{2}}[/tex]

[tex]\bf g)\: 3+|3x-1|=5[/tex]

[tex]\bf |3x-1|=5-3[/tex]

[tex]\bf |3x-1|=2[/tex]

[tex]\bf 3x-1=2\Rightarrow 3x=2+1\Rightarrow 3x=3\:|:3\Rightarrow\boxed{\bf x_{1}=1}[/tex]

[tex]\bf 3x-1=-2\Rightarrow 3x=-2+1\Rightarrow 3x=-1\Rightarrow\boxed{\bf x_{2}=-\dfrac{1}{3}}[/tex]

Hey! Am ataşat rezolvarea. :)

Vezi imaginea AlishaMasha