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AJUTORRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR!!​

AJUTORRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRRR class=

Răspuns :

Răspuns:

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Explicație pas cu pas:

x=2³³+2¹²·3²⁸+2²⁰¹⁹·3²⁴+6³⁰;   y=3²².

Restul de la împărțirea numărului x la numărul y ???  

x=y·C+R, unde R<y

x=2¹²·3²²⁺⁶+2²⁰¹⁹·3²²⁺²+(2·3)³⁰+2³³=2¹²·3²²·3⁶+2²⁰¹⁹·3²²·3²+2³⁰·3³⁰+2³³=

=2¹²·3²²·3⁶+2²⁰¹⁹·3²²·3²+2³⁰·3²²⁺⁸+2³³=2¹²·3²²·3⁶+2²⁰¹⁹·3²²·3²+2³⁰·3²²·3⁸+2³³=3²²·(2¹²·3⁶+2²⁰¹⁹·3²+2³⁰·3⁸)+2³³

Deci, x=3²²·(2¹²·3⁶+2²⁰¹⁹·3²+2³⁰·3⁸)+2³³=y·(2¹²·3⁶+2²⁰¹⁹·3²+2³⁰·3⁸)+2³³

Deci, R=2³³.  Să verificăm dacă R<y

R=2³³=(2³)¹¹=8¹¹

y=3²²=(3²)¹¹=9¹¹.

Deoarece 8<9, => 8¹¹<9¹¹, => R<y.

Răspuns: 2³³.