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Perimetrul triunghiului ABC=54 ab/2=ac/6 bc/2=ac/3 va rog, raspundeti-mi repede!!!

Răspuns :

Răspuns:

Explicație pas cu pas:

ab/2 = ac/6

ab = 2ac/6 = ac/3

bc/2 = ac/3

bc = 2ac/3

ab + ac + bc = 54

ac/3 + ac + 2ac/3 = 54

ac/3 + 3ac/3 + 2ac/3 = 54

6ac/3 = 54

2ac = 54

ac = 54 : 2 = 27

ab = 27/3 =9

bc = 2*27/3 = 18

P= AB+BC+AC

P=54

[tex]\frac{AB}{2}= \frac{AC}{6} =>AB=\frac{2AC}{6}=>AB=\frac{AC}{3}[/tex]

[tex]\frac{BC}{2}= \frac{AC}{3} =>BC=\frac{2AC}{3}[/tex]

AB+BC+AC=54

[tex]\frac{AC}{3} +\frac{2AC}{3} +AC=54\\\\\frac{AC}{3}+\frac{2AC}{3} +\frac{3AC}{3}=54\\\\\frac{6AC}{3}=54\\\\2AC=54\\\\AC=\frac{54}{2} \\\\AC=27cm[/tex]

[tex]AB=\frac{AC}{3}\\\\AB=\frac{27}{3} \\\\AB=9cm[/tex]

[tex]BC=\frac{2AC}{3} \\\\BC=\frac{2*27}{3} \\\\BC=2*9\\\\BC=18cm[/tex]