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Salut, puteti sa-mi rezolvati si mie urmatoarele ecuatii inafara de 0=0 pt a intelege cum se fac. Am atasat o poza mai jos.

Salut Puteti Sami Rezolvati Si Mie Urmatoarele Ecuatii Inafara De 00 Pt A Intelege Cum Se Fac Am Atasat O Poza Mai Jos class=

Răspuns :

Răspuns:

(x-1)²=4

x-1=√4

x-1=±2

x1=-2+1

x1= -1

x-1=2

x=2+1

x=3

x={ -11,3}

9x²-6x=15║:3

3x²-2x=5

3x²-2x-5=0

Δ=(-2)²-4*3*(-5)=

4+60=64

x1=(2-√64)/2*3=(2-8)/6= -6/6

x1= -1

x2=(2+8)/6=10/6= 5/3

(2x-1)²=9

2x-1=√9

2x-1=±3

2x-1= -3

2x= -3+1

2x= -2

x= -1

-------------

2x-1=3

2x=3+1

2x=4

x=2

x={ -1,2}

x={

Explicație pas cu pas:

[tex]\it 1)\ \ (x-1)^2=4 \Rightarrow \sqrt{(x-1)^2}=\sqrt4 \Rightarrow |x-1|=2 \Rightarrow x-1=\pm2 \Rightarrow \\ \\ \Rightarrow x-1\in\{-2,\ 2\}|_{+1} \Rightarrow x\in\{-1,\ 3\}\\ \\ 2)\ 9x^2-6x=15|_{+1} \Rightarrow 9x^2-6x+1=16 \Rightarrow (3x-1)^2=16 \Rightarrow \\ \\ \Rightarrow \sqrt{(3x-1)^2}=\sqrt{16} \Rightarrow |3x-1|=4 \Rightarrow 3x-1=\pm4 \Rightarrow \\ \\ \Rightarrow 3x-1\in\{-4,\ 4\}|_{+1} \Rightarrow 3x\in\{-3,\ 5\}|_{:3} \Rightarrow x\in\Big\{-1,\ \dfrac{5}{3}\Big\}[/tex]