(x;y) d.p. [0,(3);0,25]
x × 0,(3) = y × 0,25
x = k / 0,(3)
= k : 3/9
= k : 1/3
= k/1 × 3/1
y = k / 0,25
= k : 25/100
= k : 1/4
= k/1 × 4/1
x = 3k
y = 4k
x + y = ma × 2
= 14 × 2 = 28
=> 3k + 4k = 28
7k = 28
k = 28 / 7
k = 4
=> x = 3k = 12
y = 4k = 16
Răspuns:
Explicație pas cu pas:
0,(3) = 3/9 = 1/3
0,25 = 25/100 = 1/4
x/3 = y/4
x = 3y/4
(x + y) : 2 = 14
3y/4 + y = 28
3y/4 + 4y/4 = 28
7y/4 = 28
y = 28*4/7 = 16
x = 3*16/4 = 12
