Răspuns:
C.
Explicație pas cu pas:
Metoda 1.
2,1(4) =193/90 = 99*193/99*90=19107/8910
2,(14)=212/99=90*212/90*99=19080/8910
2,14=90*99*2,14/90*99=19067,4/8910
2.144=90*99*2,144/90*99=19103,04/8910
Ignorand numitorul comun, numararoarele se scriu ordonat:
19067,4 < 19080 < 19103,04 < 19107 , deci in consecinta
2,14 < 2,(14) < 2,144 < 2,1(4)
Metoda 2.
2,(14)= 2,14(14) = 2,14 + 0,00(14) = 2,141(41) = 2,141 + 0,000(41)
2,144= 2,141 + 0,003 = 2,141 + 0,000(41) + 0,002(58)
2,1(4)= 2,144(4) = 2,144 + 0,000(4)
Asadar
2,(14) = 2,14 + 0,00(14)
2,144 = 2,(14) + 0,002(58)
2,1(4) = 2,144 + 0,000(4),
deci
2,14 < 2,(14) < 2,144 < 2,1(4)
