Răspuns:
a.STIU formula generala CnH2n
n+2n=9---> n=3 CH2=CH-CH3 propena
b. in ordinea scrisa sp2 sp1 sp3
c CH2=CH-CH3 + HCl--> CH3-CHCL-CH3 aditie 2 cloropropan
+Cl2---> CH2Cl_CHCL-CH3 aditie 1,2 dicloropropan
+cL2---> CH2=CH-CH2CL+HCL substitutie clorura de alil
M,C6H6=42g/mol
M,C6H6Cl2= 113g/mol
din ecuatie deduc masa teoretica de produs(1,2 dicloropropan)
42g..propan............113gprodus
84g..................................x= m,teor= 226g
m,practic=226x90/100g=203,4g
Explicație:
