[tex]$f: D \rightarrow \mathbb{R}, f(x) = \frac{11}{2 + \log(5x)}$\\\text{Observam ca numitorul nu poate fi 0, iar expresia din logaritm nu poate fi negativa sau 0}[/tex][tex]$2 + \log(5x) \neq 0 \implies \log(5x) \neq -2 \implies 5x \neq 10^{-2} \implies x \neq \frac{1}{500}$[/tex]
[tex]5x > 0 \implies x > 0[/tex].
[tex]$\boxed{D = (0, \frac{1}{500})\cup(\frac{1}{500}, \infty)}$[/tex]
