Răspuns:
Explicație:
1.
MCaCl2 = 40 + 2 . 35,5 = 111---------> 111g/moli
MAgNO3 = 108 + 14 + 3 .16 = 170 -------> 170 g/moli
2
CaCl2
r.a.= 1 : 2
r.m.= 40 : 71
AgNO3
r.a. = 1 : 1 : 3
r.m.= 108 : 14 : 48= 54 : 7 : 24
3 COMP. PROC.PRIN MASA MOLARA
CaCl2
111 g CaCl2------------40g Ca-----------71 g Cl
100 g---------------------x------------------------y
x= 100 . 40 : 111 =36,036 % Ca
y= 100 .71 : 111 =63,97% Cl
AgNO3
170 g AgNO3--------108g Ag---------14gN---------48 g O
100g ---------------------x-----------------------y-----------z
x= 100. 108 : 170=63,52% Ag
y= 100. 14 : 170= 8,24% N
z= 100.48 : 170=28,24% O
