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sa se determine energia cinetica a unui corp cu masa de 2 t care parcurge cu viteza constanta distanta de 1840m in 2 minunte​

Răspuns :

[tex]m=2 t=2000 kg\\t=2 min=120 s\\d=v*t=>v=\frac{d}{t} =\frac{1840}{120}=15,33 m/s\\ E_c=\frac{mv^2}{2}= \frac{2000*15,33^2}{2}=1000* 235,111=235111 J=>E_c=235111 J[/tex]