Răspuns:
(x+2)^2/2 - (x-3)(x+3)/3=(2x-1)/2+
(x-1)^2/6
(x^2+4x+4)/2-(x^2-9)/3=(2x-1)/2+
(x^2-2x+1)/6
3(x^2+4x+4)/6-2(x^2-9)/6=3(2x-1)/6+
(x^2-2x+1)/6
(3x^2+12x+12)/6-(2x^2-18)/6=
(6x-3)/6+(x^2-2x+1)/6
(x^2+12x+30)/6=(x^2+4x-2)/6 /×6
x^2+12x+30=x^2+4x-2
12x-4x= - 2-32
8x= - 32 /:8
x= - 4
Explicație pas cu pas: