1.-2x+1-1=-2×
2. x/3=2×-1/×
x^2=6x-3
×^2-6×+3=0
×^2-2•×•3+9-6=0
(×-3)^2=6
[tex]x - 3 = \sqrt{6} \\ x = \sqrt{6 } + 3[/tex]
Cred ca asa vine...dar nu sunt sigura
3.Aria=h•b/2
24=h•b/2
h•b=48=>AC•BD=48
Deoarece BD mediana si D exiata pe AC => AD=DC
triunghiul BCD; m(D)=90°
A=c1•c2/2=BD/2•AC/2=BD•AC/4=48/4=12cm^2
