Răspuns:
Explicație:
2Fe + 3Cl₂→2FeCl₃
A Fe=56g/mol
M FeCl₃ =56+3×36,5=56+106,5=162,5 g/mol
Conform ecuatiei avem:
2 moli Fe.....................3 moli Cl₂................2 moli FeCl₃
2×56 g Fe......................................................2×162,5 g FeCl₃
Dar in 112 g Fe...........................................................x
x= 112×2×162,5÷2×56⇒x=2×162,5=325g FeCl₃care exprimate in moli sunt 2moli(n=m/M=325/162,5)
FeCl₃(s) + H₂O(l) → Fe³⁺(aq) + 3Cl⁻(aq)
