a)
[tex] \frac{x + 1}{2} = \frac{x + 2}{3} \\ 3(x + 1) = 2(x + 2) \\ 3x + 3 = 2x + 4 \\ 3x - 2x = 4 - 3 \\ x = 1[/tex]
b)
[tex] \frac{ - x + 3}{4 - x} = \frac{2}{3} \\ 2(4 - x) = 3( - x + 3) \\ 8 - 2x = - 3x + 9 \\ 3x - 2x = 9 - 8 \\ x = 1[/tex]
c)
[tex] \frac{1}{ - 2x + 3} = \frac{ - 2}{x} \\ x = - 2( - 2x + 3) \\ x = 4x - 6 \\ x - 4x = - 6 \\ - 3x = - 6 \\ x = - 6 \div ( - 3) \\ x = 2[/tex]
