d: 2x-5y +3=0
panta m=2/5
A(-2; 1) si B (0; 3/5)
B(0; 3/5) ∈ d; (0-5•3/5+3=0)
deci, vom calcula ecuatia dreptei d' ll d, dusa prin A(-2; 1)
d' ll d => panta m’=m=2/5
Ecuatia dreptei de panta m’, prin punctul A(xA,yA) :y–yA=m’(x–xA), (m≠0)
d’: y-1=2/5 (x+2)
d’: 5y-5=2x+4
d’: 2x-5y+9=0