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cum rezolv 3X×X + 10X +3=0?​

Răspuns :

Salut!

3x²+10x+3=0

a=3

b=10

c=3

Δ=b²-4ac

Δ=10²-4x3x3

Δ=100-36

Δ=64

X₁₋₂= -b±√Δ/2a

X₁=-10+8/6 = -2/6 = -1/3

X₂= -10-8/6 = -18/6 = -3

Succes!

3X×X+10X+3=0

3X²+10X+3=0

3X²+9X+X+3=0

3X(X+3)+X+3=0

(3X+1)×(X+3)=0