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Aratati ca :   [tex] x^{3} [/tex] - 2x² - 5x +6 = (x-1)(x+2)(x-3)

Răspuns :

(x-1)(x+2)(x-3)=(x²+2x-x-2)(x-3)=(x²+x-2)(x-3)=x³-3x²+x²-3x-2x+6=x³-2x²-5x+6