Răspuns:
-calculez moli H2SO4
c,m= niu/V----> niu=2x4mol=8molH2SO4
-deduc moli BaSO4 din ecuatia chimica
1mol............1mol
H2SO4 + BaCO3---> BaSO4 +CO2+H2O
8mol...........x=8molBaCO3
M,BaCO3=197g/mol
m,pur= niuxM= 8X197g=1576g
m,impur= m,pur/p unde p=80%----> m,i=1576x100/80=1970g
1molH2SO4..........1molBaSO4
8mol.........................x=niu=8moBaSO4
M,BaSO4=233g/mol
m,BaSO4= niuxM= 8X233g=1864g
100g hartie.........40gBaSO4
X..................................1864
X=4660g=4,66kg hartie NU !
Explicație: