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16^13+|2^50-8^17|
urgent pls​


Răspuns :

Răspuns:

16^13=2^52

8^17=2^51

2^51>2^50. rezulta ca modulul se desface astfel:

2^52+2^51-2^50=2^50(2^2+2^1-1)=2^50(4+2-1)=2^50×5

[tex]\it 16^{13} =(2^4)^{13}=2^{52}\\ \\ 8^{17}=(2^3)^{17}=2^{51}\\ \\ |2^{50}-8^{17}|=|2^{50}-2^{51}|=|2^{51}-2^{50}|=|2\cdot2^{50}-2^{50}|=|2^{50}|=2^{50}[/tex]

Exercițiul devine:

[tex]\it 2^{52}+2^{50}=2^2\cdot2^{50}+2^{50} =5\cdot2^{50}[/tex]