Răspuns:
a) √3(x-2)+2√3(x+1)=6√3
x√3-2√3+2√3x+2√3=6√3
3√3x=6√3 /:3√3
x=2
b) 2√3(x+2)+4√6=3√3(2x+2√2)-2√3 /:√3
2(x+2)+2√2=3(2x+2√2)-2
2x+4+2√2=6x+6√2-2
4x=6-4√2 /:2
[tex]x=\frac{3-\sqrt{2}}{2}[/tex]
e) 2√3(x+√6)-x(√3+1)=7√2-x
2√3x+2√18-√3x-x=7√2-x
√3x=7√2-6√2
√3x=√2
[tex]x=\frac{\sqrt{3} )\sqrt{2}}{\sqrt{3}} =\frac{\sqrt{6}}{3}[/tex]
f) 5√2(x-√8)-2(x-5)=x(3√2-2)
5√2x-5√16-2x+10=3√2x-2x
2√2x=10 /:2
[tex]x=\frac{5}{\sqrt{2}} =\frac{5\sqrt{2}}{2}[/tex]
g) √5(x+√10)-2√3(3-x√10)=7x√5+5√2
√5x+5√2-6√3+2√30x=7√5x+5√2
2√30x-2√5x=6√3 /:2
x√5(√6-6[tex]x=\frac{(\sqrt{6}+6) 6\sqrt{3}}{5(\sqrt{6}-6)} =\frac{6\sqrt{18}+36\sqrt{3}}{5(6-36)} =\frac{18\sqrt{2}+36\sqrt{3}}{-25} =-\frac{18(\sqrt{2}+2\sqrt{3}}{25})[/tex])=6√3
Explicație pas cu pas:
