Răspuns:
[tex]n = {16}^{2008} \div {2}^{8002} [/tex]
[tex]n = ( {2}^{4} ) {}^{2008} \div {2}^{8002} [/tex]
[tex]n = {2}^{8032} \div {2}^{8002} [/tex]
[tex]n = {2}^{32 - 2} [/tex]
[tex]n = {2}^{30} [/tex]
Răspuns:
(2^4)^2008:2^8002=2^8032:2^8002=2^30=(2^10)^3=(2^15)^2
Explicație pas cu pas:
