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a+b=7 si c-b=25 atunci 103a+100b+3c=?


Răspuns :

a+b=7 /×103

c-b=25 /×3

103a+103b=721

3c-3b=75 (+)

103a+100b+3c=721+75

103a+100b+3c=796

a + b = 7 => 103a + 103b = 7×103 = 721

c - b = 25 => 3c - 3b = 25×3 = 75

adunam relatiile

103a + 103b + 3c - 3b = 721 + 75

103a + 100b + 3c = 796