8)
xA = -rad(2) + 1
xB = rad(2) + 1
L = xB - xA = rad(2) + 1 - (-rad(2) + 1) = 2 * rad(2)
L = 2 * rad(2)
11) A(rad(2)), B(rad(3)), C(rad(8) = 2 rad(2)), D(2 rad(3))
AB = xB - xA = rad(3) - rad(2)
BC = xC - xB = rad(8) - rad(3) = 2 rad(2) - rad(3)
CD = xD - xC = 2 rad(3) - 2 rad(2) = 2(rad(3) - rad(2))
AB + BC + CD = xD - xA = 2 rad(3) - rad(2) = 2*1.73-1.41 = 3.46-1.41 = 2.05 > 2
Deci: AB + BC + CD = 2.05 > 2
