a) sin<A=30=1/2
sin<A=BC/AC=11/AC
1/2=11/AC ⇒AC=2*11=22
BM-med ⇒ BM=AC/2=22/2=11
b)AC=BM*2=9*2=18 (cred ca era AC)
c)BM=AC/2=16/2=8
BC/AC=1/2
BC/16=1/2 ( din sin<A)
BC=16/2=8
mas<C=180-(mas<A+mas<B)=180-(90+30)=180-120=60
ΔBMC
BM=BC=8
mas<C=60 ⇒ΔBMC-echilateral ⇒P=3l=3*8=24
d)ΔBMC-echilateral ⇒l=15:3=5
AC=2*MC=2*l=2*5=10