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c+d=92
cx2=dx6
c,d?
met grafica daca se poate!


Răspuns :

|_______|__| = 92(c+d=92);

|_______|_______|(c x 2) 
=
|__|__|__|__|__|__|(d x 6);

|_______|_ _| ⇒c=92-d ;
 
|_______|_______|[(92 - d) x 2] 
=
|__|__|__|__|__|__|(d x 6);

|__| 
=
|__|_ _ _ _ _|_ _ _ _ _| (d=[tex] \frac{184}{8} [/tex]=23)

|_______| c
=
|________|__| - |__| 92 - d
 c= 69