1) in prima zi parcurge 20/100×350=70km
au ramas de parcurs 350-70=280 km
in a doua zi parcurge 40/100*280=112 km
raman de parcurs in a treia zi 280-112=168 km
comparand avem: 70<112<168
2) notam masura suplementului cu x
celalaltunghi are masura 5x
obtinem atunci 5x+x=180grade ⇒6x=180 grade ⇒x=30 grade⇒ 5x=150 grade
unghiul are masura de 150 grade