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Ajutama si pe mine te rog :3 2/3(2x+4) - 3/2 (3x+ 2)=10

Răspuns :

[tex]\frac{2}{3}(2x+4)-\frac{3}{2}(3x+2)=10 \\ \\ \frac{4x+8}{3}^{(2}-\frac{9x+6}{2}^{(3}=10^{(6} \\ \\ 2(4x+8)-3(9x+6)=60 \\ \\ 8x+16-27x-18=60 \\ \\ -19x-2=60 \\ \\ -19x=60+2 \\ \\ -19x=62 \\ \\ =\boxed{-\frac{62}{19}}[/tex]