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ce nr lipseste

2; 6; 12; 12; 0;   ?.


Răspuns :

Termenul general al sirului este:
[tex]\displaystyle a_n = \frac{-19 n^3+132 n^2-209 n+120}{n+11} \\ 2, 6, 12, 12, 0, -\frac{486}{17} , -\frac{232}{3}, ...[/tex]