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[tex] x^{2} +2mx+m^{2} [/tex]-1=0
Aratati ca ecuatia are solutii distincte


Răspuns :

[tex]\triangle=b^2-4ac=(2m)^2-4(m^2-1)\\ \triangle=4m^2-4m^2+4\\ \triangle=4>0[/tex]
Cand o ecuatie de gradul doi are [tex]\triangle>0[/tex], stim ca va avea doua radacini reale distincte.