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Rezolvati ecuatia: [tex]2 x^{2} + y^{2} +2xy+2x+1=0[/tex]

Răspuns :

[tex](x^2+2xy+y^2)+(x^2+2x+1)=0\\ (x+y)^2+(x+1)^2=0\\ x+y=0 \ si \ x+1=0=> x=-1 \ si \ y=-x=-(-1)=1[/tex]