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X+     + √3 = x-2    x∈R
√3+2


Răspuns :

Aducem la acelasi numitor si obtinem:

[tex]x+1+3+2\sqrt3=x\sqrt3+2x-2\sqrt3-4[/tex]

Trecem termenii cu x in dreapta:

[tex]4\sqrt3+8=x+x\sqrt3\Rightarrow x=\dfrac{4(\sqrt3+2)}{\sqrt3+1}=\dfrac{4(\sqrt3+2)(\sqrt3-1)}{2}=2(1+\sqrt3)[/tex]