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Daca 3x+4y+5z+27=59 determinati 5z+3x+4y

 

Stiind ca x-2×y+13=52 determinati 3x-6y+1



Răspuns :

3x+4y+5z+27=59
3x+4y+5z=59-27
3x+4y+5z=32
x-2y+13=52        se determina 3x-6y+1
x-2y=52-13    deci x-2y=39
3x-6y+1=3x(x-2y)+1=3x39+1=117+1=118