Gf(x) intersectat Gg(x)=A (x;y)
A(x;y) ∈G f(x) ⇔f(x)=y
f(x)= -3x+4 ⇒ -3x+4=y (1)
A(x;y) ∈ G g(x) ⇔g(x)=y
g(x)= x/3 +1 ⇒ x/3 +1=y (2)
Din (1) ∧ (2) ⇒ -3x+4= x/3 +1 aducem la acelasi numitor
-9x+12=x+3
-9x-x=3-12
-10x=-9
10x=9
x=9/10
x/3 + 1 =y
9/10/3 + 1=y
9/10* 1/3 +1=y
3/10 +1=y aducem la acelasi numitor
3+10=10y
13=10y
y=13/10 ⇒A(9/10 ; 13/10)