x : 6 = c1 rest 5
x = 6×c1 + 5 | +1
x + 1 = 6×(c1 + 1)
x : 8 = c2 rest 7
x = 8×c2 + 7 |+1
x + 1 = 8 ×(c2 + 1)
x : 20 = c3 rest 19
x = 20×c3 + 19 |+1
x + 1 = 20×(c3 + 1)
am notat cu c1; c2 si c3 caturile celor 3 impartiri
x + 1 = c.m.m.m.c (6; 8; 20)
x + 1 = 2^3 × 3 × 5
x + 1 = 120
x = 120 - 1
x = 119 ( numarul)
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119:6 = 19 rest 5
119:8 = 14 rest 7
119:20 = 5 rest 19
