1) ΔABC-echilateral⇒AB=AC=BC⇒Perimetru=3AB⇒AB=12,6:3=4,2
2) |2x+x|=5
a) 2x+x=5
3x =5
x=[tex] \frac{3}{5} [/tex]
b) 2x+x=-5
x=[tex]- \frac{5}{3} [/tex]
A={[tex] \frac{5}{3};- \frac{5}{3} [/tex]}
3) b-bursa
b+x=450⇒b=450-x
b×2=450+x
Scadem cele doua relatii:
b=2x
Inlocuim in prima relatie:
2x+x=450
x=150
b+150=450
b=300