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Dau 14 puncte celui care ma ajuta sa rezolv calculu:
Calculati media geometrica a umerelor a=| [tex] 4\sqrt{6} - 7\sqrt{2} | [/tex] si b =[tex]| 4 \sqrt{6} + 7\sqrt{2} |[/tex]


Răspuns :

[tex] m_{g} = \sqrt{a*b} [/tex]
[tex]4 \sqrt{6}-7 \sqrt{2} = \sqrt{ 4^{2}*6} - \sqrt{ 7^{2}*2}= \sqrt{16*6} - \sqrt{49*2} = \sqrt{96} - \sqrt{98} [/tex], deci
[tex]a=7 \sqrt{2} -4 \sqrt{6} [/tex]
[tex]a*b=(7 \sqrt{2} -4 \sqrt{6} )(7 \sqrt{2} +4 \sqrt{6})[/tex]
folosim formula : [tex](a-b)(a+b)= a^{2} -b^{2} [/tex]
[tex]a*b=(7 \sqrt{2} ) ^{2} -(4 \sqrt{6} ) ^{2} =98-96=2 \\ m_{g} = \sqrt{a*b} = \sqrt{2} [/tex]